Q:: 32 Consider the following assembly language instructions:
What is the true in ax register after execution of above instructions?
(1)0270H (2)0170H
(3)01E0H (4)0370H
The 'c' register content looks like
UGC-NET January 2017 Assembly Language Question with Explanation, Assembly language, assembly programs, cbse NET January 2017 Assembly Language Question with Explanation,UGC-NET January 2017 Assembly Language programs with Explanation,
mov al, 15
mov ah, 15
xor al, al
mov cl, 3
shr ax, cl
add al, 90H
adc ah, 0
What is the true in ax register after execution of above instructions?
(1)0270H (2)0170H
(3)01E0H (4)0370H
Answer:: (1)
Explanation::
mov al, 15
It means move 15 to lower part of 'ax' register
mov ah, 15
It means move 15 to higher part of 'ax' register
The 'ax' register content looks like
0000111100001111
xor al,al
It means 'XORing lower part of 'ax' register with its own content and storing result back in 'al' , now the 'ax' register content will be
00001111
00001111
xor00000000
'ax' register content:: 0000111100000000
move cl,3
It means move 3 to lower part of 'cx' register
The 'c' register content looks like
0000000000000011
shr ax, cl
It will shift right and rotate content of 'ax' register
The 'ax' register content looks like
0000000111100000
add al, 90H
Add hexadecimal 90 to al
0000000111100000
It will shift right and rotate content of 'ax' register
The 'ax' register content looks like
0000000111100000
add al, 90H
Add hexadecimal 90 to al
0000000111100000
0000000010010000
+0000001001110000
adc ah,0
It means addition with carry which does not affect 'ax' register
So, content of ax register will be 0270H.
UGC-NET January 2017 Assembly Language Question with Explanation, Assembly language, assembly programs, cbse NET January 2017 Assembly Language Question with Explanation,UGC-NET January 2017 Assembly Language programs with Explanation,
Add hexadecimal 90 to al
ReplyDeleteCAN U PLZ EXPLAIN THE VALUE OF al
ax= 0000000111100000
Delete90H=0000000010010000 --> (0090)
After addition result is
0000001001110000
Please explain one more time
ReplyDelete