Tuesday 29 December 2015

UGC-NET DECEMBER 2015 ANSWER KEY PAPER 1

ANSWER KEY OF PAPER 1 – CBSE UGC NET EXAM 27 DECEMBER 2015 (UNOFFICIAL)

CBSE UGC NET December 2015 Answer Key – Unofficial.




UGC-NET DECEMBER 2015 COMPUTER SCIENCE ANSWER KEYS AND DESCRIPTIVE SOLUTION

http://cbsenetmaterial.blogspot.in/2015/12/ugc-net-december-2015-computer-science.html

NATIONAL ELIGIBILITY TEST (NET)
On behalf of UGC, the Central Board of Secondary Education announces holding of the National Eligibility Test (NET) on 27th December, 2015 (SUNDAY) for determining the eligibility of Indian nationals for the Eligibility for Assistant Professor only or Junior Research Fellowship & Eligibility for Assistant Professor Both in Indian universities and colleges. CBSE will conduct NET in 83 subjects at 88 selected NET Examination Cities spread across the country.
The candidates who qualify for the award of Junior Research Fellowship are eligible to pursue research in the subject of their post-graduation or in a related subject and are also eligible for Assistant Professor. The universities, institutions, IITs and other national organizations may select the JRF awardees for whole time research work in accordance with the procedure prescribed by them. The award of JRF and Eligibility for Assistant Professor both OR Eligibility for Assistant Professor only will depend on the performance of the candidate in all three papers of NET. However, the candidates qualifying exclusively for Assistant Professor will not be considered for award of JRF.

Q1) Greater the handicap of the students
Answer: 3 (Teacher)
Q2) Characteristics of Continuous and Comrehensive Evaluation
Answer: 3 (b, c and d)
Q3) Which of the following attributes denote great
Answer: 4 (a, b, c and d)
Q4) which statement is correct in context of multiple choice questions
Answer: 4 (They are more subjective than true-false questions)
Q5) As chairman of an independent commission on education
Answer: 3 (Learning : the Treasure Within)
Q6) What are required for good teaching
Answer: 1 or 4 ()
Q7) Which of the following statements is not true in the context
Answer: 4 ()
Q8) Which of the following statements is true in the context of testing of a Hypothesis
Answer: 2 (It is only the null Hypothesis, that can be tested)
Q9) Which of the following are the basis rules of APA style
Answer: 2 (b, c and d)
Q10) Which of the following are the main characteristics of a seminar
Answer: 4 (a, b and d)
Q11) A researcher is interested in studying the prospects
Answer: 1 (Rating scale)
Q12) Ethical norms in research
Answer: 1 (Thesis Format)
Q13) When confronted with signing a big card
Answer: 1 (State of Confusion)
Q14) According to author, which one is not the most creative
Answer: 4 (Reading)
Q15) The entire existence of the author revolves round
Answer: 2 (a and b only)
Q16) How many teens, as per the Bic Survey, do not own a Pen
Answer: 4 (100)
Q17) What is the main concern of the Author
Answer: 4 (That the teens have forgotten the art of Handwriting)
Q18) The main objectives of student evaluation
Answer: 2 (b, c, and d only)
Q19) Using the central point of the classroom communication as the beginning
Answer: 1 (Systemization)
Q20) Aspects of the voice, other than the speech
Answer: 4 (Delivery Language)
Q21) Every type of communication is affected by its
Answer: 4 (Context)
Q22) Attitudes, actions and appearance in the context of classroom
Answer: 2 (Non verbal)
Q23) Most often, the teacher student communication is
Answer: 3 (Utilitarian)
Q24) In a classroom commuter’s trust level determined by
Answer: 4 (eye contact)
Q25) Next Term in the series 2,5,10,17, ….
Answer: 1 (50)
Q26) Group of 210 students appeared in tesr
Answer: 4 (72)
Q27) Anil after travelling 6 km towards east
Answer: 4 (10 km)
Q28) Next Term in the series B2E,….
Answer: 4 (J58Q)
Q29) A party was held
Answer: 2 (14)
Q30) P and Q are brothers
Answer: 3 (uncle)
Q31) Consider the argument given below, pre-employment testing of
Answer: 2 (Analogical)
Q32) Among the following propositions two are related in such a way
Answer: 4 (a and d)
Q33) a cluster of propositons with a structure 
Answer: 2 (An Argument)
Q34) Consider the following Assertion (A) and reason 
Answer: 1 (Both A and R are true but R does not)
Q35) A definition that has a meaning that is deliberately
Answer: 3 (Stipulative)
Q36) If the proposition ‘No men are Honest’ is taken to be false
Answer: 2 (Some men are honest)
Q37) which decade registered the..
Answer: 1 (1961-71)
Q38) Average decadal growth rate 
Answer: 2 (0.0982)
Q39) Based on the Average decadal growth rate 
Answer: 2 (38.49)
Q40) In 1951 power availability per person
Answer: 4 (500W)
Q41) In which decade the average power availability
Answer: 3 (2001-2011)
Q42) By what %age power increased from 1951 to 2011
Answer: 4 (9)
Q43) NMEICT stand for
Answer: 1 (National Mission on education Through ICT)
Q44) Instant Messaging application
Answer: 4 (a, b and c)
Q45) A byte consists of 
Answer: 2 (8 bits)
Q46) which is not input device
Answer: 4 (Monitor)
Q47) Open source software
Answer: 3 (Mozila Firefox)
Q48) Same letter to different persons in MS word
Answer: 4 (Mail Merge)
Q49) Inside Rural homes, the source/sources of Nitrogen Oxide Pollution
Answer: 4 (a, b and c)
Q50) Which of the following pollutants
Answer: 3 (Lead)
Q51) Assertion A : People population
Answer: 1 (Both A and R are true and R is correct)
Q52) which is not natural Hazards
Answer: 4 (Chemical Contamination)
Q53) National climate change policy
Answer: 4 (350 GW)
Q54) per capita energy consumption
Answer: 3 (Russia, China, Brazil, India)
Q55) Rashtriya Uchattar Shiksha Abhiyan
Answer: 2 (a, b and c)
Q56) The grounds of which discrimination in admission
Answer: 2 (a, b and c)
Q57) Which of the following are correct about Lok Sabha
Answer: 1 (a and c)
Q58) Public order in constitutuion
Answer: 2 (The State List)
Q59) The term of office of the advocate General
Answer: 4 (Not Fixed)
Q60) Highest no of seats in Lok Sabha
Answer: 1 (Maharashtra)

Monday 28 December 2015

UGC-NET DECEMBER 2015 COMPUTER SCIENCE ANSWER KEYS AND DESCRIPTIVE SOLUTION

Answer keys and descriptive solution of UGC-NET Computer Science held on December 28, 2015 is available on 
or

Corrections and Suggestions are Welcomed

UGC-NET DECEMBER 2015 ANSWER KEY PAPER 1


http://cbsenetmaterial.blogspot.in/2015/12/ugc-net-december-2015-answer-key-paper-1.html
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Friday 18 December 2015

UGC-NET COMPUTER SCIENCE PAPER-3 SEPTEMBER 2013 WITH ANSWER KEY




UGC-NET COMPUTER SCIENCE PAPER-3 SEPTEMBER 2013 WITH ANSWER KEY




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UGC-NET COMPUTER SCIENCE PAPER-2 SEPTEMBER 2013 WITH ANSWER KEY

UGC-NET COMPUTER SCIENCE PAPER-2 SEPTEMBER 2013 WITH ANSWER KEY

Wednesday 2 December 2015

UGC-NET COMPUTER SCIENCE OPERATING SYSTEM QUESTIONS WITH EXPLANATION

In this Blog we are providing all the UGC-NET Computer Science previous year Questions with explanation:

Q :  For the implementation of a paging scheme, suppose the average process size be x bytes,
the page size be y bytes, and each page entry requires z bytes. The optimum page size that
minimizes the total overhead due to the page table and the internal fragmentation loss is
given by
(A) x/2
(B) xz/2
(C) √(2xz)
(D) √(xz)/2

(UGC-NET Computer Science December 2014 )

Answer: (C)

Explanation:

Important consideration is size of pages to use. OS often has choice in this matter---many MMUs allow various different page sizes.
  • Small size: less wasted space due to internal fragmentation; fewer unused pages in memory.
  • Large page size: more efficient disk I/O, smaller page tables
If average process segment size is x; page table entry size is z bytes; page size is y,
Average amount of internal fragmentation per segment is y/2.
Average number of pages per process segment is x/y. Each page requires 'z' bytes of page table, so each process segment requires page table size of xz/y bytes.
Total overhead per segment, therefore, due to internal fragmentation and page table entries, is
xz/y + y/2
To minimize the overhead, differentiate with respect to page size, y, and equate to 0:

-xz/y2 + 1/2 = 0
=> y = √(2xz)
So for example, if the average segment size were 256 K, and the page table entry size were 8 bytes, the optimum page size, to minimize overhead due to page table entries and internal fragmentation, would be √(2 × 256K × 8) = 2048 = 2K.
Note: that this calculation ignores the need to keep page sizes large in order to speed up paging operations; it only considers memory overheads.


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