Q::15 What is the value returned by the function f given below when n=100 ?
int f (int n)
{
if (n==0) then
return n;
else
return n + f(n-2);
}
(A)2550 (B)2556
int f (int n)
{
if (n==0) then
return n;
else
return n + f(n-2);
}
(A)2550 (B)2556
(C)5220 (D)5520
Answer: (A)
Explanation:
f(100)-->(100 + f(98)-->(98 + f(96)-->96 + f(94)........... 2 + f(0) <-- 0
So, it will be an A.P.
2 + 4 +6 +8 + ... + 98 + 100 = n(n+1) {Sum of even numbers upto 'n'}
=50 * 51 = 2550.
Hence, Option A is correct.
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